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GOMMATASARA.
पढमक्खो अन्तगदो आदिगदे संकमेदि बिदियक्खो।। दोषिणवि गंतूणतं आदिगदे संकमेदि तदियक्खो॥४०॥ प्रथमाक्ष अन्तगत श्रादिगते संक्रामति द्वितीयाक्षः। द्वावपि गत्वान्तमादिगते संक्रामति तृतीयाक्षः ॥ ४० ॥
40. The first class having come to an end (in distribution as in gatha 38) (we come) to its beginning. (Then) (the 1st element) of the second class changes (into its second element); (when all the elements of) the second class are also exhausted, (then the first elements of the 3rd class changes (into its second element), (till the whole of the 3rd class is also exhausted and we get 80 combinations.
सगमाणेहि विभत्ते सेसं लक्खितु जाण अक्खपदं। लद्धे रूबं पक्खिब सुद्धे अन्ते ण रूबपक्खेबो ॥४१॥ स्वकमानैर्विभक्त शेषं लक्षयित्वा जानीहि अक्षपदम् । लब्धे रूपं प्रक्षिप्य शुद्ध अन्ते न रूपप्रक्षेपः ॥४१॥
41. Divide the number by the number of the elements (in the class), the remainder gives the position of the ele
ment in its class. To the quotient add one. (Divide the sum by the number of the elements in the next class, the remainder again gives the position of the element in the class. And so on). (If there is) no remainder, (it means that the element is) last (in the class) (and then) one is not added (to the quotient).
Commentary, ___For example-what are the elements in combination No. 15. To find out the Vikathá element, divide 15 by 4, the remainder is 3, therefore the Vikatha is the 3rd i. e., the seditious gossip (Ráshtri Kathá). Adding one to the quotient 3, we get 4, to find out the passion divide 4 by 4, there is no remainder, that means the last passion, i. e., greed (Lobha) ; the quotient was one ; as there was no remainder, nothing to be added to it. Divide 1 by 5. the remainder is 1. the sense element is the first, i. e., touch (sparsha). Therefore the 15th combination is one of seditious gossip,
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