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58
THE INDIAN ANTIQUARY.
FEBRUARY, 1891.
Example 8. Add: 418
974 645
728 Add in the head as before and substitute the result of each row of ciphers for the uppermost cipher of the addition : thus, because 7 + 6 = 13: 13 + 9 = 22: 22 +4 = 26, write
2018
74 46
28 Theu becauso 4+2 = 6: 6 + 7 = 13: 13 + 1 = 14, write
2648
ca
Now, because 1 + 6 = 7, write
2748
Then, because 3 + 5 = 8:8 + 4 = 12:12 + 8 =20, write
3740
Then add remainder and write 2760. Demonstration by the European method is as follows:
418 974 645 723
2760. The Burmese processes, which are 6 in number, are
(a) 418, (b) 2618, (c) 2648, (m) 2748, (e) 2740, (1) 2760. 974
74
14 45
COS
645
723
23
B. SUBTRACTION.
Bxamplo l. Subtract 78 from 95. To spostract 78 from 95, place the subtractor below the integer : tens ander tens, anits acder units, and so on : thus, 95
78 Then subtract the first cipher of the subtractor from the cipher of the integer immediately above it in the head, and substitute the remainder for the first cipher of the integer : thus : 25: because 9 -7 = 2.
78
14 In cases where more than two sums are to be added togetber, the Hindus do not quite follow the proceso here described. They add the two loweet rom togother and then the result to the rom immediately above it and so on.-8. B.D.
