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152
THE INDIAN ANTIQUARY.
(JUNE, 1888.
Accordingly new-moon occurred 13 h. 23 m. Subtract 3333; the remainder 51=31.37m. before solar Phålgana, and belonged therefore Hence the 10th tithi ended 3 h. 37 m. before to Mágha. We calculate 0 Chaitra :
sunrise at Lanka, on the 3rd March, which A.D. 1231... 8104 348 51
was a Wednesday, as required. The end of the 23rd Feb. ... 1548 169 144
10th tithi being near the beginning of the 8 hours ....... 127 14 1
day, we must now consider whether the result 50 min. ...... 12 1 0
may be influenced by the geographical position
of the locality to which the record belongs; 91 532 196
viz., Girnar being about 21 minutes (of time)
west of the meridian of Lanká (or Ujjain), arg. 532......... 112
the day begins there about 21 minutes later than arg. 196......... 2
on the meridian of Ujjain. Hence the 10th
tithi ended about 3 h. 58 m. before the end of 205 = 14 hours, 31 minutes. the 3rd March. Again, the sun rises, before the
21st March, later on the circle of latitude of Accordingly, new-moon occurred 14 h. 31 m.
Girnar, than on the equator, on which Lanka before 0 solar Chaitra, and belonged therefore
is supposed to be situated. The difference still to Phålguna. In order to find éu di 10, we
more removes the end of the 10th tithi from proceed, as tsual, by adding, to the a. b. c.
the end of the 3rd March, as compared with of A.D. 1231, the a. . c. of that day after the
the same moment at Lanka. The date, as we 22nd February, the a. of which is next below
have found it, stands, therefore, proof against 4929 (or the index for su di 10).
all doubts which can be raised against it. As A. D. 1231 ... (11) 8404 348 51
regards the week day, the (11) shows that 3rd March. ... (0) 4596 496 169
it was the fourth day or Wednesday 28
required. (11) 3000 844 220
2nd method. In calculating the date, we arg. 6 844, eq.............24
can also start from A.D. 1232, the Christian arg. c 220, eq.............1
year in which the date fell. But, in that case,
we must make use of the first part of Table 7. A. = 3025 = 1 h. 46 m.
We shall sum up the figures for the 3rd March
A.D. 1232:As A. for bu di 10 is between 3000 and 3333, A.D. 1832 ... (1) 9128460 3 we see that the 10th tithi was running at the 6 Cent .......... (4) 2876 beginning of the 3rd March. That it ended
3 March ....... (6) 995 250 170 in the same day, is evident from the fact that the a, of the 4th March, vis. 4935, is, by itself,
(11) 2999 845 220 larger than the index for su di 10, which we have found to be 4929, and will become still | Comparing this result with that found above, more so by adding the equations of b. and c. we see that a. is smaller, b. larger, by one, Let us calcnlate also the 4th March
than found above. This difference is caused A.D. 1231... 8404 348 51
by our neglecting fractions below, and count4th March... 4935 532 171
ing them as 1 if larger than
4th Example.-An intercalary month. As a 3339 880 222
month in intercalated when two new-moons
occur within one solar month-one soon after arg. 6. 880, eq....44
the beginning, and the other shortly before the
end, of the solar month,--all that is required arg. c. 222, eq. ... 1
to decide any case, is, to calculate the phase of - A. 3384
the moon on the beginning and the end of the solar month. If the moon was waning at the
135
47
* The last method must be followed in cases in which the Hindu year begins in Karttika (Sept.- Oct.), and the
date in question is later than March of the succeeding English year.
