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OCTOBER, 1889.]
SCHRAM'S TABLES FOR HINDU DATES.
291
Table 1, century 800, old style...............2013 257 Table 2, year 79, October, + 20 ............ 29 148
Sum 2042 405; and Table 1, century 1800, new style ......2378 495 Table 2, year 89, February, + 10............ 32 549
Sum 2411 044. Two other remarks are necessary. When calculating for one of the years 1700, 1800, 1900, 2100, 2200, 2300; 2500, etc., new style, one should in Table 2 use the line 00 g. K.}, (and not the line 00). Accordingly, for the 3rd February, A.D. 1800, we find :
Table 1, centary 1800, new style .....................2378 495 Table 2, year 00{g. K. }, February, + 3 ......... 35
Sum 2378 530. When calculating for a year B.C., we should bear in mind that years are given here as counted by the astronomers, who count the year commonly called 1 B.C. as 0, the year 2 B.C. as - 1, the year 3 B.C. as - 2, and so on. The number expressing years B.C. must therefore be diminished by 1, to get the negative number of years counted in the astronomical manner. Moreover, it must not be forgotten that, whilst the number of the centuries B.C. in Table 1 are negative, the number of years in Table 2 are always positive; and that therefore, in case we had to calculate e.g. for-813, we would have to take - 900 from Table 1, and 87 from Table 2, because - 900 + 87 = -813; in other words, we must always take from Table 1 the preceding century, exactly as in the case of years A.D. we take the completed) preceding century. If then we should have to find the day corresponding to the 18th February, B.C. 3102, we should have (since B.C. 3102 = - 3201 = - 3200 + 99): -
Table 1, century - 3200 ....................552 257 Table 2, year 99, February + 18 .................. 36 209
Sum 588 466; i.e. the 18th February, B.C. 3102, corresponds to the day 588 466 of the Julian period.
If, on the contrary, the day of the Jalian period be given, and we have to find the corresponding day of our calendar, we must first substract from the given number of days the next lower number in Table 1 to find the century. From the remainder we must substract the next lower number in Table 2; the place which this number occupies in Table 2 gives the year and the month, and the remainder gives the day of the month. For instance, having to find the date corresponding to the day 2042 405 of the Julian period, we have -
given number of days ................ 2042 405 - next lower number in Table 1 old style ............... 2013 257 = century 800, old style ;
Remainder 29 148 - next lower number in T. 2. 29 128 = year 79, October ; Remainder
20; i.e. the day 2042 405 of the Julian period corresponds to the 20th October, A.D. 879, old style.
Here, again, the substraction of the number in Table 2 can be easily made, without writing it down. Thus, for converting the day 2411 044 into a date of new style, we simply have the following calculation : -
given number of days............ 2411 044 - next lower number in Table I, new style......2378 495 = centary 1800, new style;
Remainder 32 549 = year 89, February; remainder 10, i.e. the day 2411 044 of the Julian period corresponds to the 10th February, A.D. 1859. new style.
