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90
GANITASĀRASANGRAHA.
(at the rate of) 24 angulas in a day and half; the water (thereof) flows out through a pump (at the rate of) 24 angulas (of the well in depth) in 14 days; 1} angulas of water in depth) are lost in a day by evaporation owing to the heating) rays of the sun; a tortoise below pulls down 57 angulas of the stalk of the lotus plant in 34 days. By what time will the lotus be on the same level with the water (in the well)?
31. A powerful unvanquished excellent black snake, which is 32 hastas in length, enters into a hole (at the rate of) 74 angulas in y of a day; and in the course of of a day its tail grows by 23 of an angula. O ornament of arithmeticians, tell me by what time this same (serpent) enters fully into the hole
Thus end the (problems bearing on associated) forward and baokward movements.
The rule of operation relating to double, treble and quadruple rule-of-throo.
32. Transpose the Phala from its own place to the other place (wherein a similar concrete quantity would occur); (theu, for the purpose of arriving at the roquired result), the row consisting of the larger number of different quantities) should be, (after they are all multiplied together), divided by the row consisting of the
82. The transference of the Phala and the other operations herein mentioned will be clonr from the following worked out example. The data in the problem in stanzn No. 36 aro to be first represented thus:9 Manis.
1 Viha + 1 Kumbha. 3 Yojanax.
10 Yijanas. 00 Panas. When the Phala hero, viz., 60 panas, is transferred to the other row we have 9 Manis.
1 Váha + 1 Kumbha = 1+ Väha. 3 Yojanas.
10 Yojanas.
60 Panas. Now the right hand row, consisting of a larger number of different quantities, should be, after they are all multiplied together, divided by the smaller left hand row similarly dealt with. Thon we have
1 x 10 x 60
9 X 3 The result hero gives the nomber of panas to We found out.
