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CHAPTER VI-XIXED PROBLEMS.
known weight of) the corresponding (variety of) gold, gives rise as a matter of course, to the required varnas.
An example in illustration thereof.
188. If, the component) carnax not being known, tho resulting parna ohtained by mrcans of two different kinds of) gold weighing 16 and 10 (respectively) happens to be 11, what would lio tho (respective) varnas of those two (different kinds of) gold P
Again, the rule for arriving at the unknown rurnax of two (known quantities of gold, when the resulting varna of thu mixture is known) -
189. Choose an optional rarna in relation to one (of the two given quantities of gold); what remains to be found out) mny then be arrived at ns before. In relation to the knowll quantities of all) the numerous varieties of gold oxcepting one, the rarnas nro optional; then (proceed) us beforo.
An example in illustration thereof.
190. On fusing together (two different kinds of) gold which are 12 and 14 (respectively in weight), the resulting uw na is made out to be 10. Think out and way (what) tho varnux of those two (kinds of gold are).
An example to illustrate the latter half of the rule.
191. On fusing together 7, 9, 3, and 10 (in weight respectivoly of four different kinds of gold, the resulting mixture turns out to be (gold of) 12 varnas. Give out the rurrus (of the various component kiuds of gold) separately.
The rulo regarding how to arrive at (an estimate of the valuo of) the test sticks (of gold) :
192. The varna of every stick is to be separately divided by the (given) maximum varna, and (the quotients no obtained) are (all) to be added together. The resulting sum gives (tho measure of) the required quantity of (pure) gold. From the summed up
