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CHAPTER VI-VIXBD PROBLEMB.
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say what amounts of money they (respectively) had on hand (to start with).
2645. There were six merchants. The elder ones among them gave in order, out of what they respectively bad on hand, to thoso who were next younger to them exactly two-thirds (of what they respectively had on hand). Afterwards, they all became possosaed of equal amounts of money. What were the amounts of money thoy severally) had on hand to start with)?
The rule for arriving at cqual amounts of money on hand, aftor a number of persons give each to vio others among thoin as much as they (respectively) huve (then) ou hand :--
2654. One is divided by the optionally chosen multiple quantity (in the problem). (To this, the mumber corresponding to the men (taking part in the transaction) is added. The first (man's) amount (on hand to start with is tbus arriveil nt). This (and the results thereafter arrived at) aro written down (in order), and each of thom is multiplied by the optional multiple number as increased by one ; and the result is then diminished by one. (Thus the money on band with each of the others to start with is arrived at).
Erumplex in illustration thereof. 266}. Each of three merchants gavo to the othors what cach of these had on hand at the time). Then they all became pokroskod of equal amounts of money. What are the amounts of money wbich they (respectively) lad on hard (to start with)!
265+. 1 he rule will be clear from the following working of the problem given in st, 266) :
1, divided by the optionally chosen inultiple l, and increased by the nomilier of perdona, 3, vivant; this is the money in the hand of the first man.
This 4, moltiplied by the optionally chomin multiplo, I, am increased by 1, becomes 8; when 1 in sabtracted from this, we get 7, which is the money on hand with the second person.
Tbin 7, ngain, treated an above, 1.c., multiplied by 2 and thon diminimbed by 1, gives 13, the money on hand with the third man.
This solution can be easily arrived at from the following equation --
+(a - b -c)= 2 26 - (a - b-c) - 2 = 40 - 2 (a - -c)
-{26 – (4 - 5 - c) – 3:
31
