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CHAPTER VII--MEASUREMENT OF AREAS.
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hastas, and the top-side is 4 hastas. What is the measure of the (basal) segments (caused by the inner perpendicular) and what of the inner perpendicular (itself)?
1861. In the case of the (quadrilateral) figure above-mentioned, the measures of the top-sido and the base are each to be taken to be less by 1 hasta. From the top of each of the two perpendiculars, & string is stretched so as to reach the foot of the other perpendioular). You givo out the measures of the innor perpendi. oular and of the basal segments caused thereby).
187}. (In the case of a quadrilateral with uncqual sides), one side is 13 hastas in measure ; the opposite side is 15 haxtas; the top-side is 7 hastas; and the base here is 21 hastax What aro the values of the inner perpendicular and of the basal segmenta (caused thereby)?
1887-1894. There is an equilateral quadrilateral figure, measuring 20 hastas at the side. From the four angles of that
VII-54, and then the measuron of the perpendiculors from the end of the topside to the base as also the measures of the boxn onts of the long rauwed by those perpendiculars have to be arrived at by thu application of the rule given in stanga VII. 46. Thon taking these MCDMUCH of the perpendiculars to be those of the pillars, the rulo given in stanza 180 abrivo in applied to rrive at the measures of the inner perpendioular and the banul Beginnt rutined thereby. The problom given in stanza 187, in however worked in it lightly different way in the Kanarono commentary. The top-Hide is supposed to be parallel to the lane, and the measures of the perpendicular und of the bunul seguents caused thoroby are arrived at by construoting & trianglo who widos are the two willen of the quadrilateral, and whose baso is equal to the differendu between the base ond thu top-side of the quadrilateral.
v
1881-1891. The figure contemplated in this problem seeds to bo this:
The inner perpendiculars referred to herein are GA and KL. To find oat thene, FE in first determined. FE, AC cording to the commentary, is said to be equal to
CN DY+DE+(ID)) Then with PE and BC or AD taken as pillars, the rule under referenco may be applied.
HEL
