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Shri Mahavir Jain Aradhana Kendra
www.kobatirth.org
Acharya Shri Kailassagarsuri Gyanmandir
142
GANITASĀRASANGRAHA.
The rule for arriving at the weights of) many component quantities of) gold (of known varnas in a mixture of known varna and weight):
185. (In relation to all the known component varnas) excepting one of them, optionally chosen weights may be adopted. Then what remains should be worked out as in relation to the previously given cases by means of the rule bearing upon the determination of an) unknown weight of gold.
An example in illustration thereof. 186. The (given) varnas (of the component quantities of gold) are 5, 6, 7, 8, 11, and 13 (respectively); and the resulting varna is in fact 9; and if (the total) weight (of all the component quantities of gold be 60, what may be the several measures in weight of the various component quantities) of gold ?
The rule for arriving at the unknown varnas of two (known quantities of gold when the resulting varna of the mixture is known) :
187. Divide one (separately) by the two (given weights of) gold ; multiply (separately each of the quotients thus obtained) by (the weight of) the (corresponding quantity of) gold and (also) by the resulting) varna; write down (both the products so obtained) in two different places ; (each of these in each of the two sets,) if diminished and increased alternately by one as divided by (the
185. The rule referred to here is found in stanza 180 above.
187. Tho ralo will become clear by the following working of the problema in stanza 188:--
ex 16 1 and 10 * 10 il are written down in two places thus: 11 11
11 Then and are added and mbtracted alternately in each of the two gets thus :
11 + 16
} and 11
• These give the two sets of answers.
1
(11 +
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