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Shri Mahavir Jain Aradhana Kendra
www.kobatirth.org
CHAPTER VII-MEASUREMENT OF AREAS.
223
The rule for arriving at the (longish quadrilateral) figure associated with a diagonal having a numerical value optionally determined :
Acharya Shri Kailassagarsuri Gyanmandir
122. Each of the various figures that are derived with the aid of the given (bējas) is written down; and by means (of the measure) of its diagonal the (measure of the) given diagonal is divided. The perpendicular-side, the base, and the diagonal (of this figure) as multiplied by the quotient (here) obtained, give rise to the perpendicular-side, the base and the diagonal (of the required figure).
An example in illustration thereof.
123-124. O mathematician, quickly bring out with the aid of the given (bijas) the (value of the) perpendicular-sides and the bases of the four longish quadrilateral figures that have respectively 1 and 2, 2 and 3, 4 and 7, and 1 and 8, for their bijas, and are also characterised by different bases. And, (in the problem) here, the diagonal is (in value) 65. Give out (the measures of) what may be the (required) geometrical figures (in that case).
The rule for arriving at the numerical values of the base and the perpendicular side of that derived longish quadrilateral figure, the numerical measures of the perimeter as also of the diagonal whereof are known :--
125. Multiply the square of the diagonal by two; (from the resulting product), subtract the square of half the perimeter; (then) get at the square root (of the resulting difference). If (this square root be thereafter) utilized in the performance of the
122. The rule is based on the principle that the sides of a right angled triangle vary as the hypotenuse, although for the same measure of the hypotenuse there may be different sets of values for the sides.
125. If a and b represent the sides of a rectangle, then a2+ b2 is the measure of the diagonal, and 2a + 2b is the messure of the perimeter. It can be seen easily that
2a +26 2
2
2a +26
+ √ √ 2 (√o + 5 ) = ( 2+ + 21
2
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÷ 2 = a; and
2
2
2a
2a
20+ 26-N2 (√F+). " ( 24+ 26 ) ° } +
2
2
These two formulas represent algebraically the method described in the rule here.
÷ 2 = b.
