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Shri Mahavir Jain Aradhana Kendra
www.kobatirth.org
Acharya Shri Kailassagarsuri Gyanmandir
250
GANITASĀRASANGRAHA.
sides (which has to be the same in value as the base line between the given pillars or bills), the segments (of the base caused by the meeting of the perpendicular from the vertex with the base) are arrived at in accordance with the rule laid down already. If the values of these (segments) are written down in the inverse order, they become the values of the two perpendicular sides of the two longish quadrilaterals in the required operation. Then, in accordance with the rule given already, the values of the diagonals of the two longish quadrilateral figures may be arrived at with the aid of the values of those two sides of the triangle above mentioned which are taken here as the two horizontal sides of the longish quadrilateral) and of those two perpendicular sides. These (diagonals) are of equal numerical value.
Examples in illustration thereof.
2041-205. One pillar is 13 (hastas in height). The other is 15 (hastas in beight). The intervening distance (between them) is 14 (hastas). A rope (having its two ends) tied to the tops of these two pillars) hangs down so as to touch the ground some where between the two pillars). What are the values of the two segments, (so caused, of the base-lino between the pillars)? The two (hanging) parts of the rope are (in their length) of equal numerical value. Give out also the rope-measure.
206-2071. The height of (one) hill is 22 (yöjanus). That of another hill is 18 (yojanas). The intervening space between the two bills is 20 (Yojanas in length). There stand two religious mendicants, (one) on the top of each, who can move along the sky. For the purpose of begging (their food), they came down
0
..C2 =
Now,
a + CS=0+ cm, .. (cg + c) (c2 - C1)=0 -62; and + C2=c; 22 - 62
a? - 52
c
--- and c =These values are obviously those of the segments of the base c of a triangle having the sides a and b, the segmente having been caused by the perpendicular from the vertex. This is what is stated in this rule. Vide rule given in stanza 49 above.
..C2 =
2
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