________________
-
5/4
+
]
12 -> Figure 21
Again if the above field (Fig. 20) is bisected through its midcourse, then we get two fields. Place them upward (urdhava) as in Fig. 21.
The Analysis of the Verse 327 (TLS, p. 271)
The length (bhujā) and breadth (koti) of this field (Fig. 21) are 12 and 12 yojanas respectively. That is, they are equal (sama). In the verse, it is said as "the square of a dimension (31141afa)". Here the area of the face IJKL of the Fig. 21 is
12.12 = d.d
144 = ? Here we have to subtract the area of half FD. Therefore, in the verse it is said as "subtract half of the face (mukhadalahina)".
The area of half FD
1.2 = 2 = = TEM
From the area of the square-form-field (Fig. 20) if we subtract the number two which is equal to half the face 'm', we get
144 - 2 = d? m/2
142 = d - m/2.
Now the remaining field (avasistaksetra) is the Fig. 196. Its face-area
Arhat Vacana, 14(1), 2002
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