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If these three parts (khandatraya) are placed in the form of unit length abscissa), then we get the field as shown in Fig. 17.
(bhuja
Bisect this field (Fig. 17) through the midcourse (tiryagrupa) (i.e. thickness=5) and then place them side by side (pārsva). For this, vide Fig. 18.
Again if the above field (Fig. 18) is bisected through its midcourse (thickness =), then we get two fields (Fig. 19a and 19b). Place them separately.
1
46
2
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5/4
2
Figure 19a
5
2.
2
In this way, we find two fields. Both of them are equal to 4 Therefore one (Fig. 19a) of them has to give the SD. In other words, the SD will be remitted by one of them.
Now if the fractionless big field (tribhāgarahitavṛhatkṣetra) (Fig. 15) is bisected through its midcourse (tiryagrupa) (thickness), then we get two fields. For placing them side by side (pārsva), vide Fig. 20
6
5/2 →
2
6
5/4
← 6
Figure 20
2
Figure 19b
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