Book Title: Epigraphia Indica Vol 02
Author(s): Jas Burgess
Publisher: Archaeological Survey of India

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Page 564
________________ TABLES FOR CALCULATING HINDU DATES. 489 (e) Add the sum of equations to the distance; the result is the true distance at mean sunrise for the place in question, viz. 255° 28' 9"- 2° 44′ 44′′-252° 43′ 25′′. (f) Find the sidereal longitude of the sun by subtracting from the above the O's an., the same for beginning of the century. (Table XIII.) Sid. Long. O - K.Y. 4128 (g) Find the ayanámsas for the year in question, by Table XXVIII K.Y. 4100 = 7° 30' 0" 28 years= 25′ 12′′ 7° 55′ 12 317° 19' 44" 282° 44' 16" 34° 35' 28" (1) Add the ayanámsas thus found to the sidereal longitude of the sun, the result is the tropical longitude of the sun. 34° 35' 28" 7° 55′ 12′′ Trop. Long. = 42° 30′ 40′′ (i) Look out in Table XXVII the "interval of rising" of the degree of trop. now found for the latitude of the given place. Long. If the left-hand index (0-180) is used, the amount is subtractive; if the index to the right (180°-360°) the amount is additive. In this case we get, for trop. Long. 42° on the 28th parallel,- 1gh. 460. (k) Take, from the same part of the Table just used, the time required by one degree in rising, as given there immediately below the degree of latitude in question, and calculate the equivalent in time for the sun's equation. If the equation has the sign+, the amount is subtractive; if -, it is additive. In the present case: 1° takes up 8-24 vináḍis, consequently 1° 29′ will take up 120. The equation being negative, the amount is additive. We put it down as + 120. (1) Add (or subtract according to the sign) the vináḍts in (k) to the result in (); find the increase of Dist. -O for the sum, in Table XXII; add the increase (or subtract according to the sign of the sum) to the true Dist. - (found in e). The result is the true Dist. < for true sunrise at the place in question. Here - 1gh. 46v. +12v. = 1gh. 34v. 1gh. 34v. 1gh. = 12' 11" 84v. 6' 54" -19' 5 This, added to the result in (e), vis., 252° 4 52", makes 252° 24' 20". (m) This result is not quite correct, because we have made use of the mean increase (or decrease) of Dist. <- O instead of the true, as the Hindus do. However, we may rest satisfied with this approximation when the true distance comes out larger or smaller, by 4 minutes or more, than an entire number of degrees marking the end of a Tithi. This is the case in the present example: 252° mark the end of the 21st tithi or the 6th tithi of the dark fortnight; but as we found the true distance to be 259" 24 20", which is more than 4' above the end of the Tithi, viz. 252, the final result is not affected by the slightly incorrect calculation. In rare cases where the strictest accuracy is required, proceed as follows:Add the increase (or decrease) of the distance, etc., for the sum found in (1) to the 32

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