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## The Fifth Karma Granth
Multiplying the six bhangas of the twenty-two with the bhangas of the others, we get 445 = 24 mujakars. There are twelve mujakars in the third gunasthan, because binding the seventeen and binding the twenty-two results in 2 x 6 = 12 bhangas. In the fourth, there are twenty mujakars, because binding the seventeen and binding the twenty-one results in 244 - and binding the aim ma results in 2 x 6 = 12, thus 12 + 8 = 20 bhangas. In the fifth gunasthan, there are twenty-four mujakars, because binding the thirteen and binding the seventeen results in 242 = 4, binding the twenty-one results in 244 = 8, and binding the twenty-two results in 246 = 12, thus 4 + 8 + 12 = 24 bhangas. In the sixth, there are twenty-eight mujakars, because binding the nine and binding the thirteen results in 2224, binding the seventeen results in 242 = 4, binding the twenty-one results in 244, and binding the twenty-two results in 246 = 12, thus 4 + 4 + 8 + 12 = 28 bhangas. In the seventh, there are two mujakars, because in the seventh, binding the nine with one bhang and dying results in binding the seventeen with two bhangas. In the eighth gunasthan, there are also two mujakars, the same as in the seventh. In the ninth gunasthan, there are three mujakars each in the five bandhastanas of five, four, etc., which are due to the falling of one and the dying of two. Thus, there are one hundred and twenty-seven mujakar bandhas.
The forty-five alpatar bandhas are as follows:
Appadara pun tisam nam pam chhatoni boni nam ev. Yule panagavone ekavark antim sune. || 473
In the first gunasthan, there are thirty alpatar bandhas. From the second gunasthan onwards, up to the apurvakaran gunasthan, the alpatar bandhas are zero, zero, 6, 2, 2, zero, 1 in nature. In the ninth gunasthan, there is one alpatar bandha of the nature of pan, etc., but in the fifth part of the end, there is zero, i.e., no alpatar bandha. The explanation is as follows:
In the first mithyatva gunasthan, there are thirty alpatar bandhas, because binding the twenty-two and binding the seventeen results in 6 x 2 = 12, binding the thirteen results in 6 x 2...