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## Chapter 414 / Go. Sa. Jivakanda
**Second Part**
When the second part is placed on top of the first part, a square area with a diameter of the fourth part of the **utkrista** number and a **praayam** equal to the diameter is formed. When this is combined with the previous area, which has a diameter of the fourth part of the **utkrista** number and a **praayam** of three-fourths of the diameter, an area with a **pramaan** of the **utkrista** number and a diameter of one-fourth of the **pramaan** is formed. Its **pramaan** is:
```
00
0
0000000000000000
?
20 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 400
00
```
**Verses 323-331**
```
0000
16
0000ooooooo
```
Here, taking the **utkrista** number as the **pishul**, there is a **sankaatbhaagavrudhi** projection. Therefore, all the projections are one-fourth of the **utkrista** number. When these (4) projections are combined with the previous three-fourths of the **utkrista** number (12) projections, there are **utkrista** number (16) **sankaatbhaagavrudhi** projections. All these together form a **jghanya** space. When this is combined with a **jghanya** space, there is a double increase. The remaining **pishul** and **pishula pishul** remain in the same position. This is also the gross meaning.
Now, we will describe the subtle meaning in relation to this. By dividing the **utkrista** number into fifty-six parts, forty-one parts go forward from the first **sankaatbhaagavrudhi** space or descend fifteen parts from the last space of the **utkrista** number **sankaatbhaagavrudhi** spaces, creating a space of double increase there. For example, when forty-one parts are situated by climbing up, there are forty-one parts of total projections in that space.
Now, when there are fifteen parts of total projections, a **jghanya** space is created. We will explain the method of their creation. The number of **pishul** related to that space is only the sum of forty-one parts (41).
**Doubt:** Why don't we say that it is less than one digit?
**Solution:** No, because due to its **stoka** nature, it does not have prominence here.
Then, when they are equated, an area is formed with a **praayam** of forty-one parts and a **trishkambh** of half of forty-one parts - 2034. To take an area of fifteen parts wide and forty-one parts long within this area, one should separate and establish a separate area of five parts wide and forty-one parts long, leaving a diameter equal to fifteen parts of **pishul** from the first **praayam** and exceeding by half a part. Then, one should separate and establish a separate area with a diameter of half a part and a **praayam** of forty-one parts. Then, one should cut and separate an area with a diameter of one part and a **praayam** of one part. The remaining area from this taken area is 34. This area...