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After giving two examples related to the lost (Nasta), now we give examples to make the intended (Uddishta) net. We need to find the number of the 'Food-story-speaking, illusionary, eye-sense-subdued, sleepy, affectionate' (Bhojanakathalaapi Mayaavi Chakshuindriya ke Vashibhut Nidralu Snehavan) Palapa. The number for Food-story is two, the number for illusionary Kshaya is eight, and the number for eye-sense is forty-eight. Adding these three (2 + 8 + 48 = 58), we get 58. Therefore, the number of the above 'Food-story-speaking, illusionary, eye-sense-subdued, sleepy, affectionate' Palapa is 58. Similarly, the Palapa of other lost (Nasta) and the intended (Uddishta) of other Palapa should be found.
**Doubt:** Why were the brackets not made for sleep-inattentiveness (Nidra Pramad) and affection-inattentiveness (Sneha Pramad) in verses 43 and 44?
**Solution:** There are not two and three initial-answer-differences (Praadi Uttar Bhed) for sleep-inattentiveness (Nidra Pramad) and affection-inattentiveness (Sneha Pramad), therefore, their brackets were not made. Even if the brackets were made, putting zero in place of sleep-inattentiveness (Nidra Pramad) and zero in place of affection-inattentiveness (Sneha Pramad), and adding these two zeros, would not make any difference in the number, therefore, the brackets for sleep-inattentiveness (Nidra Pramad) and affection-inattentiveness (Sneha Pramad) were not made.
**Or:** There are 37,500 divisions (Bhang) of inattentiveness (Pramad), which are as follows: two divisions of affection (Sneha), five types of sleep (Nidra), five senses (Indriya) and mind (Man) making six, Kshaya and non-Kshaya together making twenty-five, and twenty-five Vikatha. Multiplying these together (2 x 5 x 6 x 25 x 25 = 37,500), we get 37,500 divisions (Bhang).
To find the lost (Nasta) and intended (Uddishta), the instrument (Yantra) is made in such a way that there are as many rows (Pancti) in the instrument as there are original divisions (Mula Bhed). There are as many compartments (Kothe) in the row of the original division (Mula Bhed) as there are answer-differences (Uttar Bhed) of that original division (Mula Bhed). The original divisions (Mula Bhed) and answer-differences (Uttar Bhed) are written in order. In the compartments of the first row, the numbers one, two, three, etc. are written in order. Below that, in the first compartment of the second row (Ananta Anubandhi), zero is written. In the second compartment, the number (25) that was written in the last compartment (Sangitavadya Katha) of the first row is written, because there is no row before this first row. In the third and subsequent compartments (Ananta Anubandhi Maya Adi) of the second row, the number of the second compartment (Ananta Anubandhi Man) is doubled (25 x 2 = 50), tripled (25 x 3 = 75), quadrupled (25 x 4 = 100), etc. up to 25 x 24 = 600. Below the second row, in the first compartment (Sparshendriya) of the third row (Indriya), zero is written. The number (25) of the last compartment of the first row and the number (600) of the last compartment of the second row are added together, and the resulting number (625) is written in the second compartment (Ramana) of the third row (Indriya). After this, in the third and subsequent compartments, the number of the second compartment is doubled (625 x 2), tripled (625 x 3), quadrupled (625 x 4), etc. in order. Similarly, in the compartments of the fourth, fifth, etc. rows, zero is written in the first compartment (Styanagaddhi) and in the second compartment (Nidvani Nidra), the sum of the numbers of the last compartments of the previous rows {25 + 600 + 3125 = 3750} is written, and in the Nritoay and subsequent compartments, the number of the second compartment is doubled (3750 x 2), tripled (3750 x 3), etc. Adding the numbers of the last compartments of each row together gives the total number of divisions (Bhang). According to this method, two instruments are made for the two presentations of the 37,500 divisions (Bhang) of inattentiveness (Pramad), which are as follows: -