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EPIGRAPHIA INDICA.
sideration. These three elements for the several parts into which a date is divided, must be summed up; and complete revolutions rejected,
With the resulting <'s anomaly and o's anomay, turn to the Table XXIV, for the equation; take the corresponding equations (interpolating for values intermediate between those in the table), find their sum or difference as the equations are additive or subtractive. The sum or difference, according to its sign, must be added to, or subtracted from, the mean distance to obtain the true distance of sun and moon for the moment calculated. As 12° indicate one tithi, we find the number of tithis elapsed since the instant of the last conjunction or amávásya by dividing the degrees of the equated distance by 12; the quotient shows how many tithis are gone.
We have found above ($ 25) that Åshadha-sudi 12 K. Y. 8585, occurred on 2nd Sravana. Mr. Dikshit has calculated the same date according to several Siddhantas, (Corp. Insc. Ind. vol. III, introd. p. 167), and he states that according to the Súrya Siddhanta the 12th tithi ended 51 gh. 11 p. after mean sunrise at Lanka. First compute K. Y. 3585, 2nd Sråvaņa, according to the Súrya Siddhanta :
C's an. O's an.
Cor. 3500 K. Y. . 323° 0' 0" 40° 29' 30" 282° 45' 25" -29 gh. 52 p.
85 years . 126 749 268 1 92 0 0 0 + 0 *21* 2nd Srávan. 58 44 23 135 2 88 91 89 89 28 31
Sums. 502 52 11448 33 35 374 25 4
Or . 142 52 11 88 33 35 14 45 4 As shown by.Cor.', we must retrench the increase for 23 gh. 31 p. to find the value of the elements for mean sunrise at Lanka. But as we have to calculate their amount for 51gh. 11p. after sunrise, we add that time to Cor.' vis.--23gh. 31p. + 51gh. 11p. = + 27gh. 40p. We therefore add the increments for 27 gh. 40 p. (Table XXII for ghatikás and palas) to the above result:
Dist. 3585 K. Y., 2nd Sråv. 142° 52' 11"
14° 25' 4" 27 gh. 5 299 5 52 45
26 37 & # 8 42
39 148 29 28 9 33 21 1 4 52 20 We have now to find the equation for the a's anomaly. In Table XXIV, we have the equation for C's anomaly 86° 15' = -5° 2' 9". The difference between the given ('s anomaly and this is 3° 20'. The increase of the equation for one minute of anomaly A is (:"16, accordingly for 3° 20' or 200 it is 32". Added to the above equation this makes - 5° 2' 41.96
In the same way we find the equation for the O's anomaly 14° 52' = + 0° 34' 4". The sum of both equations = - 4° 28' 37, added to 148° 29' 28' gives 144° 0' 51" for the true distance of sun and moon. As a tithi is equal to 12° of distance, 144o marks the end of the 12th tithi, and the distance 51' is equal to about 4 palas (Table XXII), by which time the end of the tithi occurred before the moment calculated by Mr. Dikshit."
Let us now calculate the same date according to the Brahma Siddhanta and the
C's an.
O's an.
40 p.
* In all these calculations care should be had to take the tables for the same Siddhanta throughout the process; only Tables XXI and XXII equally apply to all Siddhantas.
In this instance it would have been easier to start from anomaly 90°, and subtract the increase for 25', the resulting equation will then be found to be 5°2' 42", which is more correct.
I cannot account for the difference in the ronalt, but I abould think that the native method of calculation admits of various abbreviations of the process which in the end bring about a slightly different result.