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## Appendix]
To divide 6954 yojanas by 61, we get 114 yojanas.
Adding 114 yojanas to 3111 yojanas, we get 3225 yojanas, which is the increase in the circumference of the 183rd circle. Adding 3225 yojanas to the circumference of the innermost circle, which is 315089 yojanas, we get the circumference of the outermost circle, which is 318314 yojanas.
The original text of this formula states that the circumference of the outermost circle is 318315 yojanas. This should be understood practically. Because when we calculate the circumference of each circle, a remainder of 375 yojanas increases. Multiplying this by 183 circles, we get 68625. Dividing this number by 2150, we get 31. Since this is more than the expected 61 half-parts, it is considered complete in practice and is stated as 318315.
Ka
Formula 2.3
The speed of the Sun in each circle per muhurta
The difference between each circle is 2 yojanas 48/61 parts. The difference between both the Sun's circles is 5 yojanas 35/61 parts. The area of the entire circle is 510 yojanas.
Formula 20
|| The first prabhrit is the eighth prabhrit-prabhrit ends ||
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That is, in 2 days and nights, both Suns complete one circle.
The specific speed of the Sun in each muhurta can be known from this formula -
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Speed in 1 muhurta = Circumference of the circle / Muhurtas in 2 days and nights
According to 30 muhurtas in 1 day and night, there are 60 muhurtas in 2 days and nights.
The circumference of the innermost circle is 315089 yojanas.
Both Suns complete the revolution of the innermost circle in 60 muhurtas.
When the Sun transitions between circles, it transitions with its own specific speed. Both the Suns of Bharat Kshetra and Airāvata Kshetra transition with their specific speeds and complete one circle in 60 muhurtas.
The speed of the Sun in 1 muhurta in the innermost circle
Circumference of the innermost circle / 60 muhurtas = Speed in 1 muhurta.
315089 yojanas / 60 muhurtas = 5251 yojanas 29/60 parts is the speed of the Sun in 1 muhurta.
Practically, there is a difference of 18 yojanas in the circumference of each circle. That is, adding 18 yojanas to the circumference of the innermost circle, we get the circumference of the next circle. Accordingly,