________________
JANUARY, 1978
or
NH
NH+99000
.. NH
and
Also we have
JR
<FAJ
<AOJ
1000 y
1000 y. (given).
It suggests that height NH is preserved in terms of JR (depression of Meru inside the flat earth) and the diameter ED was theoretically generated as shown before.
Now the various angles are computed as below:
OJ
50000
<OAJ tan-1
<NOJ
<P'OK'
<P'AK'
=
..<P'
=
tan-1
tan-1
tan-1
500
50000
-
AJ
FJ
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AB
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AJ
OJ
NJ
OJ
(GH y2 GB, and NJ
<AOG
<OAF
<PGK <OAJ + <AOG = 23°.96 By assumption iv, we have
23°.96 and
= <OAJ = 24°.45 = <PAK < POK
<AOJ <NOJ = 2°.12 <OAJ <FAJ = 21°.84
tan-1
―
tan-1
tan-1
= tan-1
<P
-
=
0°.49
110000
5000
110000
110000
50000
100000
50000
... Latitude of the observer (in India) situated at 0, perhaps Ujjain (23°.90 N) or Patna (25°.37 N)
= 23°.5
NH+HJ)
Since P' and P are very far off from 0 and they are close to each other, <P is almost equal to <P' for all practical purposes, i.e.
<P = 0°.49 <POK = <PGK
- 24°.45
23°.47
= 23°.5 approx.
i.e. The true altitude of the celestial north pole is 23°.5.
Since altitude of celestial north pole is equal to the terrestrial latitude of the observer,
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= 2°.61
87
65°.55
= 63°.43
(2)
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