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________________ No. 111 History of Mathematica in India from faina Sources 61 2. PARALLELOGRAM : The area of a parallelogram is equal to the length of its base multiplied by its height. Fig. 6 Construction. Cut the portion (4 perpendicular to #9) and take it to the other side (06). The resultir:g figure is a rectangle, hence the theorem. First Principle of Deformation: If one of the sides of a parallelo gram is moved along itself, the area of the parallelogram remains unchanged. In the figure 9 a 7; 8 sliding in its own line is moved to the position giving the rectangle of equal arca. 3. TRIANGLE: The area of a triangle is equal to half the length of its base multiplied by its height. This result is true because a triangle is half of a parallelogram on the same base and of the same height. Second principle of deformation. If the vertex of a triangle is moved parallel to the base, the area of the triangle remains unchanged. Fig. 7.
SR No.010080
Book TitleBabu Devkumar Smruti Ank
Original Sutra AuthorN/A
AuthorA N Upadhye, Others
PublisherJain Siddhant Bhavan Aara
Publication Year1951
Total Pages538
LanguageHindi
ClassificationSmruti_Granth
File Size47 MB
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