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(A.) Gautam ! Multiply the circumference of Jambu island by 3. 4 Divide the resultant by 10. The result arrived at is the perimeter. 5. (The perimeter of Jambu island = 3,16,228; 3,16,228 x 3 = 9,48,684; 9,48,684 + 10 = 94,8684)
[Q. 4) Reverend Sir! What is the length of area of heat at that time ? 4i (Ans. ] Gautam ! It is 78,333 yojan at that time.
The distance between Meru and outer edge of Jambu island is 45,000 yojan. Lavan Ocean is of 2,00,000 yojan and if one-sixth of this distance namely 33,3334 yojan is added to the said distance of 4,500 the heat region arrived is 78,3331 yojan. Its shape is like that of the front part of the central rod of a cart.
IQ. 5] Reverend Sir! What is the shape and the length of its zone of 4 darkness ? 4. (Ans. ] Gautam ! The shape of the zone of darkness is like Kadamb
flower facing upwards. It is narrow from inside and wide from outside (It is like semi-circle from inside and wide-spread creeper from outside, it is like the face of a person in cross-legged sitting posture from inside and from outside it is like the central rod of a cart.
The length of its innermost arm close to Meru mountain is 6.
4
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yojan.
(Q. 6] Reverend Sir ! How has this length been calculated ?
(Ans. ] Gautam ! Multiply the circumference of Meru by 2. Divide the resultant by 10. This is the desired perimeter
(Circumference of Meru = 31,623; 31,623 x 2 = 63,246; 63,246 + 10 = 6,324o yojan.)
The perimeter of its outermost arm close to Lavan Ocean is 63,2456 yojan.
[Q. 7) Reverend Sir ! How has this perimeter been calculated ?
[A. ] Gautam ! Multiply the perimeter of Jambu island by 2. Divide the result by 10. The resultant is the desired perimeter.
(The perimeter of Jambu island = 3,16,228; 3,16,228 x 2 = 6,32,456; 6,32,456 + 10 = 63,245 yojan.)
10. 8] Reverend Sir ! What is the length of the area of darkness at that time ?
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| सप्तम वक्षस्कार
( 491 )
Seventh Chapter
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