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Scientific Secrets of Jainism
f' = c and hence according to E Enhf, energy becomes infinite and wavelength becomes zero.
And if v = c, i.e. the source of light and the light-approached the surface go far apart from each other with a velocity c. If the approaching surface is steady then the source of light goes far and far from it. Therefore
_ . 1- v/c , 0 according to the equation
0, the resultant frequency
V1+vic becomes zero, wavelength becomes infinite and energy beomes zero i.e. photon will remian steady or motionless.
Suppose for the Doppler's Effect, the situation is as follows:
A is a source of light which is steady and B, C and D are the objects from which B has velocity + v i.e. it goes far from source of light A, with a velocity v, C is steady and D has velocity -v, i.e. it comes nearer to the source of light.
Now according to Einstein's equation, frequency of the same photons of the same source of light is different for B, C and D objects. For the object B frequency of photon decreases, while for the D object frequency of the same photon increases, at the same time for object C, it remains constant, What a strange situation it is !
Though this is mathematically true yet in practical life and logically it is not appropriate or proper.
Actually, in Doppler's Effect frequency or the energy of each photon remains the same forever. It is not variable according to the velocity of either source of light or light approaching surface because the source of light emits photons which have always equal or the same energy and the frequency is either steady or it moves in the forward or the reverse direction.
Intensity of light or any radiation depends only on the number of photons approaching the unit area of surface per unit time. And therefore the velocity of either the source of light to the approaching surface or the approaching surface to the source of light, increases the intensity of that light. And if they are going far apart from each other, intensity of that light
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